Transform rule syntax clarifications

[Cameron Dutro via CLDR-Users]

The difference of two sets is dependent on order just as it is for
subtraction. Mark's example is identical to the "regular" difference:

{c, d} asym diff {d, e} = {c} just as {c, d} - {d, e} = {c}

What am I missing here?

-Cameron

On Tue, Nov 19, 2019 at 12:44 PM Mark Davis ☕️ via CLDR-Users <
cldr-users at unicode.org> wrote:

> Yes, typo. And thanks also to Asmus for the clarification (got lazy since
> am on phone).
>
> {phone}
>
> On Tue, Nov 19, 2019, 19:02 Richard Wordingham via CLDR-Users <
> cldr-users at unicode.org> wrote:
>
>> On Tue, 19 Nov 2019 13:14:02 +0000
>> Mark Davis ☕️ via CLDR-Users <cldr-users at unicode.org> wrote:
>>
>> > That's not it. Eg
>> >
>> > A = {c d}
>> > B = {d e}
>> >
>> > Diff (asym) = {c}
>> >
>> > Diff (sym) = {c d}
>>
>> I trust you mean
>>
>> Diff (sym) = {c e}
>>
>> ICU Unicode set 'symmetric' difference is probably more complicated.
>>
>> Richard.
>>
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