Redundancy in TR14

Karl Williamson public at
Mon Jan 11 17:32:47 CST 2016

Example 7 in

has these two rules

NU × (NU | SY | IS)

NU (NU | SY | IS)* × (NU | SY | IS | CL | CP )

It appears to me that the first rule generates a subset of what the 2nd 
rule generates, and so is useless.  It could be hence removed for 
simplicity, unless I'm missing something or there is a typo and it is 
meant to generate something else.

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